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| This picture is of the metal on the hot plate boiling. Taken by Evan Bell |
Background: Since we had to fine specific heat in this lab I had to find out what exactly it was. I learned that specific heat is the heat necessary of a substance to to raise the heat of water one degree Celsius.
Data:
Temperature:
Temp. of the water--20.3c
Temp. of water and metal--20.5c
Water boil and metal temp.--99.3c
Metal in Styrofoam cup--26.0c
Cold water--21.0c
Masses:
Mass of Beaker--116.85g
Beaker and water--257.73g
Beaker water and metal--285.7g
Beaker water and metal(boiling)--@71.89g
Styrofoam cup--2.00g
Styrofoam and water--96.55g
We found all of the temperatures by placing a thermometer into the beaker or Styrofoam cup and waiting for the temperature to leave out. We found most of the masses by finding the wiegh on a triple beam. To find the mass of the water we took the mass of the beaker without water and subtracted it from the beaker with water.
Analysis:
Calculations:
Specific heat equation--Q = m*c*∆T
water change
99.3 - 21.0=78.3c
heat water gained:
Q=(94.4)(4.184)(5)
Q=1974.848c
specific heat: for metal
Q = c
m(c)
1974.848=.897
2022.954
What I learned:
I learned from this lab was how precise the measuring has to be. Several time we had redo a measurement because we only wrote down one decimal point.
Conclusion:
In conclusion I determiner that our unknown metal was aluminum. The specific heat for aluminum is .897 and that is what our data concluded to answer.
